" The value of "int_(x(1+log x)^(2))" is "

Find the value of int((1+log x)^(2))/(x) dx

The value of int_(-(1)/(2))^((1)/(2)) cos x log((1-x)/(1+x))dx is -

The value of int_(-1)^(1) log ((x-1)/(x+1))dx is

The value of int(1)/(x+x log x)dx is 1+log x(b)x+log x(c)x log(1+log x)(d)log(1+log x)

The value of int _(-1)^(1) log ((2-x)/(2+x)) d x is equal to

The value of int _(-1)^(1) log ((2-x)/(2+x)) d x is equal to

The value of int _(-1)^(1) log ((2-x)/(2+x)) d x is equal to

The value of int _(-1)^(1) log ((2-x)/(2+x)) d x is equal to

The value of the integral int (dx)/(x (1 + log x)^(2)) is equal to

Prove that int_(0)^(1)log((x)/(x-1))dx=int_(0)^(1)log((x-1)/(x))dx . Find the value of int_(0)^(1)log((x)/(x-1))dx