x^(2)+ax+a^(2)+6a<0" for "a=?

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) a ^(2) x ^(2) + 6ax + 9

(2x ^(2) + 3x -4) (3x +2) = 6x ^(3) + ax ^(2) -6x-8 In the above equation, a is a constant. If the equation is true for all value of x, what is the value of a ?

Find the coordinates of points equidistant from the axes and lying on the circle x^(2) + y^(2) - 6x - 2y + 6 = 0 .

Find zeroes of the given quadratic polynomials and verify the relation between zeroes and coefficients : 6x^(2)+5ax-6a^(2)=0

If the circles x^(2) +y^(2) + ax -6y + 4 =0 and x^(2) + y^(2) - 12x + 32 =0 touch externally each other and if the distance between the centres is equal to 5, then the values of a are

Consider the quadratic polynomial f(x)=x^(2)-4ax+5a^(2)-6a a) Find the smalest positive integral value of a for which f(x) positive integry real x.(i) Find the largest distance between the roots of equation f(x)=0.

Factories: x ^(2) +6ax+9a ^(2)

If x +2 is a factor of x^(3) + ax^(2) + 11 x + 6 , find the value of a.

If 1, -2, 3 are roots of x^(3) - 2x^(2) + ax + 6 = 0 then a =