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A cylindrical wire is stretched to incre...

A cylindrical wire is stretched to increase its length by 10%. Calculate the percentage increase in resistance.

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When the same wire is stretched, its length increases but cross-sectional area decreases. The change in resistance is due to both increase in length and decrease in cross-sectional area.
`Volume V=1A=constant ,A=V/I=constant` `therefore R=(Pl)/A=(pI^2)/ApropI^2` `therefore R'/R=(1/1)^2`
Given `1=1+10/100 1=1.1L implies1/1=1.1 ``therefore (R')/R=(1.1)^2=1.21`
% increase in resistance `(R’-R)/R times 100%=(R’/R-1) times 100%=(1.21-1) times 100%=21%`
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