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The resisitance of a galvanometer is 5...

The resisitance of a galvanometer is `50 Omega ` and it shows full scale diflection for current of 1 mA. . To convert it into a voltmeter to measure 1V and as well as 10 V ( refer circuit diagram ) the resistance `R_(1) ` and `R_(2) ` respecivtively

A

`900 Omega and 9950 Omega`

B

``900 Omega and 9900 Omega``

C

`950 Omega and 9000 Omega`

D

`950 Omega and 9950 Omega`

Text Solution

Verified by Experts

The correct Answer is:
D
Use formula `R_s=V/I_g-R_g`
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