Home
Class 12
PHYSICS
A potentiometer wire of length 1m and re...

A potentiometer wire of length 1m and resistance `20 Omega` is connected in series with a 15V battery and an external resistance `40 Omega` . A secondary cell of emf E in the secondary circuit is balanced by 24 cm long potentiometer wire. The emf E of the cell is ,

A

2.5V

B

1.2V

C

2.0V

D

3 V

Text Solution

AI Generated Solution

To solve the problem step by step, we will follow the procedure outlined in the video transcript. ### Step 1: Calculate the total resistance in the circuit The total resistance \( R_{total} \) in the circuit is the sum of the resistance of the potentiometer wire and the external resistance: \[ R_{total} = R_{potentiometer} + R_{external} = 20 \, \Omega + 40 \, \Omega = 60 \, \Omega \] ...
Promotional Banner

Similar Questions

Explore conceptually related problems

AB is a potentiometer wire of length 100 cm and its resistance is 10 Omega . It is connected in series with a battery of emf 2V and resistance 40 Omega . If a source of unknown emf E is balanced by 40 cm length of the potentiometer wire, the value of E is :-

A potentiometer wire has a length 2 m and resistance of 10 Omega . It is coonnected in series with a resistance of 990 Omega and a cell of e.m.f. 2 V. The potential gradient along the wire is

A potentiometer wire of length 10m and resistance 20Omega is connected in series with another resistance of 80Omega and a battery of emf 4V . The potential gradient on the wire will be (in mV//cm )

A potentiometer wire of lengthh 100 cm has resistance 5Omega . It is connected in series with a resistance and a cell of emf 2 v and of negligible internal resistance. A source of emf 5 mv balanced by 10 cm length of potentiometer wire. The value of external resistance is___

A potentiometer wire of length 1.0 m has a resistance of 10 Omega . It is connected to a 6 V battery in seried with a resistance of 5 Omega . Determine the emf of the primary cell which gives a balance point at 40 cm.

A potentiometer wire of length 10 m and resistance 30 Omega is connected in series with a battery of emf 2.5 V , internal resistance 5 Omega and an external resistance R . If the fall of potential along the potentiometer wire is 50 mu V mm^(-1) , then the value of R is found to be 23 n Omega . What is n ?

A potentiometer wire of length 1 m has a resistance of 100Omega . It is connected to a 6V battery in series with a resistance of 5Omega . Determine the emf of the primary cell which gives a balance point at 40cm.