The thermal coefficient of resistivity for a material is `10^-3``/^@C`. A potential difference 100 V is applied across a conductor made out of this material at `20^@C`. Initially, the rate of total heat dissipation in the conductor is `H_0`. After some time, the conductor achieves an equilibrium temperature `100^@C` . The rate of total heat dissipation at this temperature is H .The ratio `H_0/H` is _____

Explanation

To solve the problem, we need to find the ratio \( \frac{H_0}{H} \) where \( H_0 \) is the initial heat dissipation rate at \( 20^\circ C \) and \( H \) is the heat dissipation rate at \( 100^\circ C \).

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Thermal coefficient of resistivity, \( \alpha = 10^{-3} \, /^\circ C \)
- Initial temperature, \( T_1 = 20^\circ C \)
- Final temperature, \( T_2 = 100^\circ C \)
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