A galvanometer of resistance `40Omega` can measure a current of 10mA To convert it into a voltmeter of range 8V the required resistance is ___________ `Omega`.

Explanation

To solve the problem of converting a galvanometer into a voltmeter, we need to determine the required resistance to be added in series with the galvanometer. Here’s a step-by-step solution:

### Step 1: Understand the Given Values
- Resistance of the galvanometer, \( R_G = 40 \, \Omega \)
- Maximum current the galvanometer can measure, \( I_G = 10 \, \text{mA} = 10 \times 10^{-3} \, \text{A} = 0.01 \, \text{A} \)
- Desired voltage range of the voltmeter, \( V = 8 \, \text{V} \)

### Step 2: Use Ohm's Law
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