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The emf of a cell is epsilon and its int...

The emf of a cell is `epsilon` and its internal resistance is r. its terminals are connected to a resistance R. The potential difference between the terminals is `1.6V` for `R = 4 Omega`, and `1.8 V` for `R = 9 Omega`. Then,

A

E=1v r=`1Omega`

B

E=2v r=`1 Omega`

C

`E=2v,r=2Omega`

D

E=2.5V, `r=0.5 Omega`

Text Solution

Verified by Experts

`V_(AB)=E-ir=1.6 for R=4 Omega and V_(AB)=E-ir=1.8 for R'=9 Omega i=E/(R+r), i=E/(R+r)`
Subsitute the value to get :`r=10 Omega and E=2V`
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