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The resistance of a conductor is 5Omega ...

The resistance of a conductor is `5Omega` at `50^(@)`C and `6Omega` at `100^(@)C`. The resistance at `0^(@)C` is

A

`2Omega`

B

`1Omega`

C

`4Omega`

D

`3Omega`

Text Solution

Verified by Experts

From `R_t=R_0(1+at) therefore 5=R_0(1+50a)`……….(i)
and `6=R_0(1+1000a)`…….(ii)
`therefore 5/6=(1+50a)/(1+100a) or a=1/200`
Putting the value of a in equation (i) we get `5=R_0(1+50 times 1/200) implies R_0=4 Omega`
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