A current of 2 mA was passed through an ...

A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11 V is connected across it is

A

`11 times 10^5`

B

`11 times 10^-5`

C

`11 times 10^-3`

D

`11 times 10^-4`

Verified by Experts

`P=I^2R implies 4.4 =(2 times 10^-3)^2 times R implies R=1.1 times 10^6 Omega`
Now,`P=V^2/R=(11 times 11)/(1.1 times 10^6) W=11 times 10^-5 W`

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