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The resistance of the meter bridge AB in...

The resistance of the meter bridge AB in given figure is 4 `Omega` .With a cell of emf `epsilon=0.5 V` and rheostat resistance `R_(h) = 2 Omega ` the null point is obatined at some point J is found for `R_(h) = 6 Omega " The emf "epsilon _(2)` is

A

0.3V

B

0.4V

C

0.5V

D

0.6V

Text Solution

Verified by Experts

At pull point Current `i=6/((R_h+4))`
For balance e=I
Where x is the resistance between A and I
SO case I `0.5(6x)/(2+4) implies x=0.5`
Case 2 `e_2=(6x)/10 implies e_2=0.3` volts
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