For the resistance network shown in the figure, choose the correct options (s)

Options

A. The current through PQ is zero.
B. `I_1=3A`
C. The potential at S is less than that at Q
D. `I_1=2A`

Explanation

Due to symmetry on upper side and lower side, points P and Q are at same potentials. Similarly, points S and T are at same potentials. Therefore, the simple circuit can be drawn as shown:
`I_2=12/(2+2+2)=2A implies I_3=12/(4+4+4)=1A`
`therefore I_1=I_2+I_3=3A implies I_(PQ)=0`
Because `V_p=V_O`
Potential drop (from left to right) across each resistance is
`12/3=4V therefore V_(Ms)=2 times 4=8V implies V_(NQ)=1 times 4=4V or V_s lt V_Q`