Two identical moving coil galvanometers have `10Omega` resistance and full scale deflection at `2muA` current. One of them is converted into a voltmeter of 100mA full scale reading and the other into an Ammeter of 1mA full scale current using appropriate resisters. These are then used to measure the voltage and current in the Ohm’s law experiment with `R=1000 Omega` resistor by using an ideal cell. Which of the following statement(s) is(are) correct?

Options

A. If the ideal cell is replaced by a cell having internal resistance of`5Omega` then the measured value of R will be more than `1000Omega`
B. The resistance of the Ammeter will be`0.02Omega` (round off to 2nd decimal place)
C. The resistance of the voltmeter will be `100kOmega`
D. The measured value of will be `978Omega lt R lt 980 Omega`

Explanation

To solve the problem, we need to analyze the two galvanometers and how they are converted into a voltmeter and an ammeter. We will then use these devices to measure the resistance \( R = 1000 \, \Omega \) in an Ohm's law experiment.

### Step 1: Calculate the resistance of the voltmeter

The voltmeter is designed for a full-scale reading of \( 100 \, mV \) with a galvanometer that has a full-scale deflection current of \( 2 \, \mu A \).

Using the formula for the resistance of the voltmeter:

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