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A uniform rod of mass m is bent into the...

A uniform rod of mass m is bent into the form of a semicircle of radius R. The moment of inertia of the rod about an axis passing through A and perpendicular to the plane of the paper is

A

`2/3 mR^(2)`

B

`mR^(2)`

C

`5/pi mR^(2)`

D

`2m R^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
If an identical semicircle is joined to form a complete ring of mass 2m, then `I_(A)` of complete ring by parallel axis theorem is `(2m)R^(2) + 2mR^(2)=4mR^(2)` . And if I is required moment of inertia then`2I= 4mR^(2) rArr I = 2mR^(2)`
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