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A circular disc A of radius r is made fr...

A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r is made from an iron plate of thickness `t//4`. The relation between the moments of inertia `I_(A)` and `I_(B)` is (about an axis passing through centre and perpendicular to the disc)

A

`I_(A) gt I_(B)`

B

`I_(A) = I_(B)`

C

`I_(A) lt I_(B)`

D

depends on the actual values of t and r

Text Solution

Verified by Experts

The correct Answer is:
C
`I=1/2Mr^(2) = 1/2(Ir^(2) omega)r^(2)` or `I propto tx^(4)`
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