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The centre of a wheel rolling without sl...

The centre of a wheel rolling without slipping on a plane surface moves with a speed `v_(0)`. A particle on the rim of the wheel at the same level as the centre of wheel will be moving with speed

A

`sqrt(2)v_(0)`, zero

B

`2v_(0)`, zero

C

`sqrt(2)v_(0), v_(0)^(2)/R`

D

`v_(0),V_(0)^(2)/R`

Text Solution

Verified by Experts

The correct Answer is:
C
Speed `=sqrt(v_(0) + (Romega)^(2)) = sqrt(2) v_(0)`
Acceleration `=omega^(2) R = v_(0)^(2)/R`
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