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A disc is performing pure rolling on a s...

A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in Fig,. At any instant, for the lower most point of the disc,

A

velocity is v, acceleration is zero

B

velocity is zero, acceleration is zero

C

velocity is v, acceleration is `v^(2)/R`

D

velocity is zero, acceleration is `v^(2)/R`

Text Solution

Verified by Experts

The correct Answer is:
D
`a=R omega^(2) = R(v/R)^(2) = v^(2)/R`
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