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A disc of mass M and Radius R is rolling...

A disc of mass M and Radius R is rolling with an angular speed `omega` on the horizontal plane. The magnitude of angular momentum of the disc about origin is:

A

`1/2 MR^(2)omega`

B

`MR^(2)omega`

C

`3/2 MR^(2) omega`

D

`2MR^(2) omega`

Text Solution

Verified by Experts

The correct Answer is:
C
L=mvR `+ Iomega = momega R^(2) +1/2mR^(2)omega=3//2mR^(2)omega`
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