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The moment of inertia of the body about ...

The moment of inertia of the body about an axis is 1.2 kg `m^(2)`. Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angualr acceleration of 25 `rad/s^(2)` must be applied about the axis for the duration of

A

4s

B

2s

C

8s

D

10s

Text Solution

Verified by Experts

The correct Answer is:
B
`1/2 Iomega^(2) = K.E rArr omega^(2) =(2(1500))/1.2 = 2500 rArr omega =50 rad//s`
`omega = 0 + alpha t rArr t = omega/alpha = 50/25= 2s`
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