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The moment of inertia of a system of fo...

The moment of inertia of a system of four rods each of length l and mass m about the axis shown is

A

`2/3 mI^(2)`

B

`2mI^(2)`

C

`2mI^(2)`

D

`8/3 mI^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Moment of inertia about 2:
`I_(2)=4((mI^(2))/3 sin^(2) 45^(@))=(2mI^(2))/3`
Applying parallel axis theorem,
`I_(1) = I_(2) + mh^(2) = (2mI^(2))/3 = 4m(1/sqrt(2))^(2) = theta/3mI^(2)`
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