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Average torque on a projectile of mass m...

Average torque on a projectile of mass `m` (initial speed `u` and angle of projection `theta`) between initial and final positions `P` and `Q` as shown in figure, about the point of projection is :
.

A

`(mu^(2) sin 2theta)/2`

B

`m u^(2) cos theta`

C

`m u^(2) sin theta`

D

`(m u^(2) cos theta)/2`

Text Solution

Verified by Experts

The correct Answer is:
A

`tau_(av).Deltavect = DeltaL` Here, `Deltat`= time of flight `=(2mu sin theta)/g`……….(1)
`|DeltavecL| =|(vecL_(f) - vecL_(j))|` about point of projection.
`=(mu sin theta)("range") -0 =((m u sintheta)(mu^(2) sin 2theta))/g`
`(mu u^(2) sintheta 2theta)/g therefore |vectau_(av)| =(vecDeltaL)/(Deltat) = (mu^(3) sin theta sin 2theta)/g .g/(2u sin theta) = (m u^(2) sin 2theta)/2`
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