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A disc of mass m and radius R is placed ...

A disc of mass m and radius R is placed over a plank of same mass m. There is sufficient friction between disc and plank to prevent slipping. A force F is applied at the centre of the disc.

Force of friction between the disc and the plank is

A

`F/2`

B

`F/4`

C

`F/3`

D

`(2F)/3`

Text Solution

Verified by Experts

The correct Answer is:
B

`F-f= ma_(1)`………..(1)
`f=ma_(2)`……..(2)
`alpha = tau/I = (fR)/(1/2mR^(2)) = (2f)/(mR)`……….(3)
`a_(1)-Ralpha = a_(2)`…………(4)
Solving these four equations, we get `a_(1) = (3F)/(4m), a_(2) = F/(4m), f=F/4, alpha = F/(2mR)`
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