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A hoop of radius r and mass m rotating w...

A hoop of radius r and mass m rotating with an angular velocity `omega_0` is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases ot slip?

A

`(r omega_(0))/3`

B

`(x omega_(0))/2`

C

`x omega_(0)`

D

`(x omega_(0))/4`

Text Solution

Verified by Experts

The correct Answer is:
B
From conservation of angulr momentum about any fixed point on the surface.
`mr^(2)omega_(0) = mvr + mr^(2)omega = mvr + mr^(2) (v/r)`
`rArr mr^(2)omega_(0) = mvr + mvr = 2mvr` or `v=(romega_(0))/2`.
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