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Moment of inertia of a body about a give...

Moment of inertia of a body about a given axis is `1.5 kg m^(2)`. Initially the body is at rest. In order to produce a rotational kinetic energy of 1200 J, the angular acceleration of `20 rad//s^(2)` must be applied about the axis for a duration of _________ (in sec).

A

5s

B

25s

C

2s

D

3s

Text Solution

Verified by Experts

The correct Answer is:
C
`alpha = 20 rad/sec^(2) , omega = omega_(0) + alpha t, omega = 20 t, 1/2 I omega^(2) = 1200`
`1/2 xx 1.5 xx (20t^(2)) = 1200, t=2` sec.
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