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int tan(x-alpha).tan(x+alpha).tan 2x dx ...

`int tan(x-alpha).tan(x+alpha).tan 2x dx` is equal to

A

`log |(sqrt(sec 2x).sec(x+alpha))/(sec(x-alpha))|+C`

B

`log |(sqrt(sec 2x))/(sec (x-alpha) .sec(x+alpha))|+C`

C

`log |(sqrt(sec 2x). sec (x-alpha))/(sec(x + alpha))|+C`

D

None of these

Text Solution

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The correct Answer is:
B
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