int(cos 4x-1)/(cot x-tanx)dx is equal to...

`int(cos 4x-1)/(cot x-tanx)dx` is equal to

A

`(-1)/(2) cos(4x) + C`

B

`(-1)/(4) cos (4x)+C`

C

`(-1)/(2) sin (2x) + C`

D

None of these

Verified by Experts

The correct Answer is:

D

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