int(log(x+1)-logx)/(x(x+1))dx is equal ...

`int(log(x+1)-logx)/(x(x+1))dx` is equal to :

A

`-(1)/(2)[ log ((x+1)/(x))]^(2)+C`

B

`C - [{ log (x+1)}^(2) - (log x)^(2)]`

C

` - log [ log ((x+1)/(x))]+C`

D

`- log ((x+1)/(x)) + C`

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The correct Answer is:

A

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