If int[sinx]^2/[1+[sinx]^2].dx =x-ktan^-...

If `int[sinx]^2/[1+[sinx]^2].dx` =`x-ktan^-1(M tanx)` then: a. `M=1/sqrt2` b. `k=1/sqrt2` c. `M=-1/sqrt2` d. `k=-1/sqrt2`

A

`A = (1)/(3) `

B

`B = (2)/(3)`

C

`A = - (1)/(2)`

D

`B = -(1)/(6)`

Verified by Experts

The correct Answer is:

B

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