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int 1/(a+bcosx)^2dx, a>b...

`int 1/(a+bcosx)^2dx`, `a>b`

Text Solution

Verified by Experts

The correct Answer is:
`(2)/((a^(2) - b^(2))^(3//2))[a theta - ( b tan theta)/(1+tan^(2) theta)]+c "where" tan^(2) theta = ((a-b))/((a+b)) tan^(2).(x)/(2)`
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