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The integral intcos(log(e)x)dx is equal ...

The integral `intcos(log_(e)x)dx` is equal to: (where C is a constant of integration)

A

` x [ cos (log _e x ) + sin (log _ e x )] + C `

B

` (x)/(2) [ cos (log _ e x ) + sin ( log _e x ) ] + c `

C

` x [ cos (log _ e x ) - sin (log _e x ) ] + C `

D

` (x)/(2) [ sin (log _ e x ) - cos (log _ e x ) ] + c `

Text Solution

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The correct Answer is:
B
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