Home
Class 12
MATHS
The number of values of x in (0, 2pi) wh...

The number of values of `x` in `(0, 2pi)` where the function `f(x) = (tan x + cotx)/2-|(tan x-cotx)/2|` continuous but non-derivable :

Promotional Banner

Similar Questions

Explore conceptually related problems

The number of values of x in (0,2 pi) where the function f(x)=(tan x+cot x)/(2)-|(tan x-cot x)/(2)| continuous but non-derivable:

The number of values of x int [-2pi, 2pi] satisfying tanx + cotx = 2" cosec x" is

The function f(x) = (|x+2|)/(tan^(-1)(x+2)) , is continuous for

The value that should be assigned to f (0) so that the function f(x) = (x + 1)^(cotx) is continuous

int_(0)^(pi//2) (5 tan x - 3 cotx)/(tan x + cot x) dx=

Value of f (pi/4) so that the function f(x) = (tan(pi/4-x))/(cot 2x), x != pi/4 is continuous everywhere is

The value of that should be assigned to f(0) so that the function f(x) =(x+1)^(cotx) is continuous at x = 0, is

In order that the function f(x)=(x+1)^(cotx) is continuous at x=0, f(0) must be defined as