`int_0^(2pi) cos^5 x dx=`

Evaluate: int_0^(2pi)cos^5x\ dx

Evaluate int_0^(pi/2) cos^2x dx

(i) int_0^(pi/2) sin^2 x dx (ii) int_0^(pi//2) cos^2 x dx

Prove that: int_(0)^(pi)cos^(5)x dx = 0

int_(0)^(2 pi)|cos x|dx

I=int_(0)^(2 pi)cos^(5)x*dx

int_(0)^(2 pi)cos^(5)x*dx

(i) int_0^(pi//2) cos x dx (ii) int_(-pi//2)^(pi//2) cos x dx (iii) int_0^(pi//2) cos 2x dx

Evaluate: int_0^pi |cos x| dx

Compute the integrals : (a) int_(0)^(pi//2) (cos x dx)/( 6 - 5 sin x + sin^(2) x) (b) int _(0)^(pi//2) (dx)/( 2 + cos x)