A block of mass "2kg" is placed on the floor.If "a],[" force of "2.8N" is applied on the block parallel at angle of "30" degree from horizontal,then acceleration of block is `(take "g=10m/s^(2)" )`

A block of mass 2 kg is placed on the floor . The coefficient of static friction is 0.4 . If a force of 2.8 N is applied on the block parallel to floor , the force of friction between the block and floor is : (Taking g = 10 m//s^(2) )

A rectangular block of mass 5 kg is kept on a horizontal surface . The coefficient of friction between the block and the surface is 0.2 . If a force of 20 N is applied to the block at angle of 30^(@) with the horizontal plane , what is the force of friction on the block ? (Take g = 10 m//s^(2) )

A block of mass 2 kg is placed on the floor (mu=0.4) . A horizontal force of 7 N is applied on the block. The force of friction between the block & floor is f_(s) . Find the f_(s) .

A horizontal force of 4 N is applied to a block of mass 2 kg resting on a frictionless table. What is the acceleration of the block in ms^(-2) ?

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4.A force F of 2.5 N is applied on the block, as shown. Calculate the force of friction between the block and the floor. ("g = 9.8 ms"^(–2))

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )

A block of mass 2kg is kept on the floor. The coefficient of static friction is 0.4 . If a force F of 2.5N is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

A block of mass 20 kg is placed on a rough horizontal surface. When a force of 80 N is applied at an angle of 30°with the horizontal, the block just begins to slide. What is the coefficient of static friction ? (g= 10m//s^2 )