2x=50

2x^(2)+400x+50

If x_i>0 i=1,2,3,...50 x_1+x_2...+x_50=50 then the minimum value of 1/(x_1) +1/(x_2) +...+1/(x_50) equals

If x_(i)>0i=1,2,3,...50x_(1)+x_(2)..+x_(50)=50 then the minimum value of (1)/(x_(1))+(1)/(x_(2))+...+(1)/(x_(50)) equals

If x_1gt0,i=1,2.....50 and x_1+x_2+.....x_50=50 then the minimum value of 1/x_1+1/x_2+......1/x_50 equals to.

If both the mean and the standard deviation of 50 observatios x_(1), x_(2),….x_(50) are equal to 16, then the mean of (x_(1)-4)^(2), (x_(2)-4)^(2),….,(x_(50)-4)^(2) is

If both the mean and the standard deviation of 50 observatios x_(1), x_(2),….x_(50) are equal to 16, then the mean of (x_(1)-4)^(2), (x_(2)-4)^(2),….,(x_(50)-4)^(2) is

Solve x^(2)+15x+50=0

x^(2)-50x+25=0

(x^(p^(2)))/(x^(q^(2)))=(x^(50))^(2) with xgt1 and p-q-4 , what is the value of p+q ?

to remove the 2^(nd) term of the equation x^4 -10 x^3 +35 x^2 -50 x^2 - 50 x+ 24=0 , diminish the roots by