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The entropy change can be calculated by ...

The entropy change can be calculated by using the expression `DeltaS-(q_(rev))/(T)`. When water freezes in a glass beaker, choose the correct statement amongst the following:

A

`Delta S` (system) decreases but `Delta S` (surroundings) remains the same

B

`Delta S` (system) increases but `Delta S` (surroundings) decreases

C

`Delta S` (system) decreases but `Delta S` (surroundings) increases

D

`Delta S` (system) decreases but `Delta S` (surroundings) also decreases

Text Solution

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The correct Answer is:
C

The entropy change can be calculated by using the expression
`Delta S = (q_("rev"))/(T)`
When water freezes in a glass beaker, `Delta S` (system) decreases because molecules in solid ice are less random than in liquid water, However, when water freezes to ice, heat. Hence, entropy of the surrounding increases
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