The enthalpy of vaporisation of ` C CI_(4)` is `30.5 kJ "mol"^(-1)`.Calculate the heat required for the vapourisation of 284 g of `C CI_(4)` at constant pressure. (Molar mass of ` C CI_(4) = 154u`). (Keep your answer in KJ and two digits only)

Explanation

Given that, 1 mol of `C Cl_(4) = 154 g`
`Delta_("vap") H " for " 154 g C Cl_(4) = 30.5 kJ`
`:. Delta_("vap") H " for " 284 g C Cl_(4) = (30.5 xx 284)/(154) kJ = 56.25 kJ`