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Match the species in Column I with the t...

Match the species in Column I with the type of hybrid orbitals in Column II.

Text Solution

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(A-3), (B-1), (C-5), (D-4)
A. `SF_(4)` = number of bp(4) + number of Ip(1)
`=sp^(3)d` hybridisation.
B) `IF_(5)`= number of bp(5) + number of Ip(1)
`=sp^(3)d^(2)` hybridisation.
C) `NO_(2)^(+)` number of bp (2) + number of Ip(0)
=sp hybridisation.
D) `NH_(4)^(+)` = number of bp(4) + number of Ip(0)
`=sp^(3)` hybridisation.
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Match the species in Column I with the type of hybrid orbitals in Colunm II. {:(" Column I Column II " ),((i) SF_(4) " (a) "sp^(3) d^(2) ),((ii) IF_(5) " (b) "d^(2) sp^(3)),((iii)NO_(2)^(+)" "(c)sp^(3) d ),((iv) NH_(4)^(+)" "(d) sp^(3)),(" "(e) sp ),():}

Match the species given in Column I with the hybridstion given in Column II.

Knowledge Check

  • Match the species in Column I with the bond order in Column II.

    A
    i-c,ii-d,iii-a,iv-b
    B
    i-a,ii-b,iii-c,iv-d
    C
    i-a,ii-b,iii-d,iv-c
    D
    i-a,ii-c,iii-e,iv-d
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