8x+4=3(x-1

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If (5x + 1)^3 + (x - 3)^3 + 8(3x - 4)^3 =6 (5x + 1)(x- 3)(3x- 4) , then x is equal to:

underset(x to 1//2)lim {(8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1)}=

lim_(x to 1/2)((8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1)) .

" If (3x^(3)-8x^(2)+10)/((x-1)^(4))=(3)/(x-1)+(1)/((x-1)^(2))-(7)/((x-1)^(3))+(k)/((x-1)^(2)) then "k=

Lt_(x to oo)((8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1))=

Solve : log_4 8+ log_4(x+3)-log_4(x-1)=2

Solve log_(4)(8)+log_(4)(x+3)-log_(4)(x-1)=2

Solve (log)_4 8+(log)_4(x+3)-(log)_4(x-1)=2.