[" iis "2x+y=5],[3x+2y=8]

(a) 2x+y=5 ; 3x+2y=8

(2) Solve 2x+y=5, 3x+2y=8

Solve the following pair of linear Equations by the substitution method : 2x+y=5 , 3x+2y=8 .

2x+5y=8/3, 3x-2y=5/6

8x+5y=9 3x+2y=4

3x+2y=8 2x-3y=8

5x-3y=8,3x+y=2 .

Which of the following pairs of linear equations has unique solution,no solution,or infinitely many solutions.In each there is unique solution ,find it by using cross multiplication method.(ii)2x+y-5 3x+2y=8

The line 3x + 2y = 6 will divide the quadrilateral formed y the lines x + y = 5, y – 2x = 8, 3y + 2x = 0 & 4y – x = 0 in

If 8x + 5y = 9, 3x + 2y = 4, then the value of x and y are