7x^(2)+8x-1=0

If roots of equation 8x^(3)-14x^(2)+7x-1=0 are in geometric progression,then toots are

Simplify the following : 5x^(4) - 7x^(2) +8x - 1 +3x^(2) - 9x^(2) + 7 - 3x^(4)+11x - 2 +8x^(2)

Solve: x^(4)-7x^(3)+8x^(2)+8x-8=0 given 3-sqrt(5) is a root.

Find the value of the expression for the given value of x. x^(3)+7x^(2)+8x-1 , when x= -2 .

The lengths of the tangents from any point on the circle x^(2)+y^(2)+8x+1=0 to the circles x^(2)+y^(2)+7x+1=0 and x^(2)+y^(2)+4x+1=0 are in the ratio

The lengths of the tangents from any point on the circle x^(2)+y^(2)+8x+1=0 to the circles x^(2)+y^(2)+7x+1=0 and x^(2)+y^(2)+4x+1=0 are in the ratio

The sum of 5x^(2) ,7x^(2) ,8x^(2) ,11x^(2) and 9x^(2) is …………..

Without solving , comment upon the nature of roots of each of the following equations : (i) 7x^(2)-9x+2=0 (ii) 6x^(2)-13x+4=0 (iii) 25x^(2)-10x+1=0 (iv) x^(2)+2sqrt(3)x-9=0 (v) x^(2)-ax-b^(2)=0 (vi) 2x^(2)+8x+9=0

Add 7x^(2) -8x + 5, 3x^(2) -8x +5 and -6x^(2) + 15x - 5