Let the vectors ` veca`and ` vecb`be such that `|veca|=3`and `| vecb|=(sqrt(2))/3`, then ` vecaxx vecb`is a unit vector, if the angle between ` veca`and ` vecb`
(A) `pi//6`
(B) `pi//4`
(C) `pi//3`
(D) `pi//2`

Explanation

To solve the problem, we need to determine the angle between the vectors \( \vec{a} \) and \( \vec{b} \) such that the cross product \( \vec{a} \times \vec{b} \) is a unit vector.

### Step-by-Step Solution:

1. **Understanding the Cross Product**: The magnitude of the cross product of two vectors \( \vec{a} \) and \( \vec{b} \) is given by the formula:
\[ |\vec{a} \times \vec{b}| = |\vec{a}| |\vec{b}| \sin \theta \]
...