" (3) "3x-2y=(5)/(2);(1)/(3)x+3y

Solve the following equations by Cramer’s method. 3x - 2y = (5)/(2), (1)/(3)x + 3y = - (4)/(3)

3x-2y=(5)/(2),(1)/(3)x+3y=(-4)/(3)

Find the following products and verify the result for x=-1,y=-2:(3x-5y)(x+y)(2)(x^(2)y-1)(3-2x^(2)y)((1)/(3)x-(y^(2))/(5))((1)/(3)x+(y^(2))/(5))

Solve the following simultaneous equations using Cramer's rule 3x-2y=5/2,(1/3)x+3y=-4/3 .

{:((1)/(2(x + 2y)) + (5)/(3(3x - 2y))=(-3)/(2)),((5)/(4(x + 2y)) - (3)/(5(3x - 2y)) = (61)/(60)):}

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5,5/(3x+2y)+1/(3x+2y)=6/5

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5 5/(3x+2y)+1/(3x-2y)=2

Solve the following system of equations: (2)/(3x+2y)+(3)/(3x-2y)=(17)/(5),quad (5)/(3x+2y)+(1)/(3x-2y)=2

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