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" 34."[sin10^(@)+sin130^(@)-sin110^(@)=]...

" 34."[sin10^(@)+sin130^(@)-sin110^(@)=],[1)0quad 2)-1quad 3" ) "1quad 4" ) "1/2]

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sin50^(@)-sin70^(@)+sin10^(@)=?

(i) sin10^(@)sin50^(@)sin70^(@)

2sin40^@sin10^@ =

Sin10^(@) - Sin110^(@) + Sin130^(@) =

sin 50 ^(@) - sin 70^(@) + sin 10^(@)

(1-4 sin 10^(@) sin70^(@))/(2 sin 10^(@))=

Find 1-sin10^(@)sin50^(@)sin70^(@) .

cos110^(@)+sin20=

sin50 ^ (@) - sin70 ^ (@) + sin10 ^ (@) = 0