`x/acostheta+y/bsintheta=1, x/asintheta-y/bcostheta=1` then `x^2/a^2+y^2/b^2=`

If x/acostheta+y/bsintheta=1,x/asintheta-y/bcostheta=1 ,' then prove that x/a^2 + y/b^2 =2'

If x/acostheta+y/bsintheta=1,x/asintheta-y/bcostheta=1 , then eliminate theta .

If x/a costheta+y/b sintheta=1 and x/a sintheta-y/bcostheta=1 Prove that : (x^2)/(a^2)+(y^2)/(b^2)=2

If acosheta+bsintheta=4 & asintheta - bcostheta= 3 then a^2+b^2

i) If acostheta+bsintheta=m and asintheta-bcostheta=n , then prove that: a^(2)+b^(2)=m^(2)+n^(2)

If acostheta+bsintheta=m and asintheta-bcostheta=n , then show that a^(2)+b^(2)=m^(2)+n^(2) .

If acostheta+bsintheta=m and asintheta-bcostheta=n , then show that a^(2)+b^(2)=m^(2)+n^(2) .

i) If acostheta+bsintheta=m and asintheta-bcostheta=n , then prove that: a^(2)+b^(2)=m^(2)+n^(2)

If acostheta+bsintheta=m and asintheta-bcostheta=n , then a^2+b^2= (a) m^2-n^2 (b) m^2n^2 (c) n^2-m^2 (d) m^2+n^2

lf x=acostheta+bsintheta , y=asintheta-bcostheta then show that y^2(d^2y)/dx^2-x dy/dx+y=0