`int (dx)/(2x^2-5)=`

int(dx)/(2x^2+3x+5)=

If int(x+2)/(2x^(2)+6x+5)dx =P int(4x+6)/(2x^(2)+6x+5)dx+(1)/(2) int (dx)/(2x^(2)+6x+5') Then the value of P is

If int(x+2)/(2x^(2) + 6x + 5)dx = P int (4x + 6)/(2x^(2) + 6x + 5)dx + (1)/(2) int (dx)/(2x^(2) + 6x + 5) then the values of P is a)1/3 b)1/2 c)1/4 d)2

Evaluate the following inegrals int(dx)/(x^(2)+2x+5)

int(dx)/(x-x^(2)-2.5)

Evaluate the integrals in exercise. overset(1) underset(-x) int (dx)/(x^(2)+2x+5)

Evaluate: int (dx)/(2sin^2x+5cos^2x)

Evaluate the following integrals. (i) int 1/((x - 2)^2 + 1)dx " " (ii) int (x^2)/(x^2 + 5)dx " " (iii) int 1/(sqrt(1 + 4x)^2)dx

If I=int(dx)/(x^(2)-2x+5)=(1)/(2)tan^(-1)(f(x))+C (where, C is the constant of integration) and f(2)=(1)/(2) , then the maximum value of y=f(sinx)AA x in R is