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The diameter of a roller 120cm long is 84cm. If it take 500 complete revolutions to level a playground, determine the cost of levelling it at the rate of 30 paise per square metre.

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d=120cm,l=84cm
Area of playground`=2pirl*500`
Side area of cylinder`=2pirl=2pi(60)(84)cm^2`
Area of playground`=500*2pirl`
`=500*2*pi(60)(84)cm^2`
Cost of levelling`=0.3*6*84pi=475.2Rs`.
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