The total surface area of a hollow cylinder which is open from both sides is `4620` sq. `cm` area of base ring is `115.5 sq. cm` and height `7 cm.` Find the thickness of the cylinder.

Explanation

`h=7cm`

`r=`inner radius

`R=`outer radius

Thickness=R-r

TSA=inner CSA+outer CSA+`2xx`Base Ring

Inner CSA`=2pirh`

Outer CSA`=2piRh`

Base ring area`=pi(R^2-r^2)`

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