If `A sub B` then `P(A) sub P(B)`

If A sub B, then P(A nn B^(c))=

If A sub B , then A cup B = ?

If A sub B , then A cup B = ?

Assertion (A) : If A sub B and B sub A then P(A) = P(B) Reason (R) : If A sub B then P (bar(A)) le P (bar (B))

If A sub B, then (A'nn B')=?

For all sets A, B and C, if A sub B , then A cup C sub B cup C .

For all sets A, B and C, if A sub B , then A cap C sub B cap C .

For all sets A, B and C, if A sub B , then A nn C sub B nn C .

For all sets A, B and C, if A sub B , then A uu C sub B uu C .

For all sets A, B and C, if A sub B , then A nn C sub B nn C .