A cylindrical tube, open at both ends, is made of metal. The internal diameter of the tube is 10.4cm and its length is 25cm. The thickness of the metal is 8mm everywhere. Calculate the volume of the metal

Explanation

inner Diameter=`10.4 cm`
inner radius(r)=`10.4 cm//2`=`5.2 cm`
Outer radius(R)=`(5.2 +0.8)cm`=`6cm(8mm=0.8 cm)`
volume of the tube=`pi(R^2-r^2)h`
=`22//7xx[6^2-(5.2)^2]xx25`
=`22//7xx8.96xx25`
=`704 cm^3`
Hence ,Volume of the metal=`704 cm^3`