If `A^5=O` such that `A^n != I` for `1 <= n <= 4`, then `(I - A)^-1` is equal to

If A^5=0 such that A^n != I for 1 <= n <= 4 , then (I - A)^-1 is equal to

Let A = ((1,1,3),(5,2,6),(-2,-1,-3)) and let n be the smallest value of n in N such that A^(n) = O_(3) then det (I_(3)+A+A^(2)+ cdots+ A^(n-1)) is equal to _____ .

If A = [[3,1],[-1,2]] , show that A^2-5A +7I = O

If (I-A)^(-1)=I+A+A^2+...+A^7, then A^n=O , where n is

If I_n is the area of n-s i d e d regular polygon inscribed in a circle of unit radius and O_n be the area of the polygon circumscribing the given circle, prove that I_n=(O_n)/2(sqrt(1+((2I_n)/n)^2))

If A=[{:(3,1),(-1,2):}] , show that A^(2)-5A+7I=O .

If I_n is the area of n sided regular polygon inscribed in a circle of unit radius and O_n be the area of the polygon circumscribing the given circle, prove that I_n=(O_n)/2(1+(sqrt(1-((2I_n)/n)^2))

The reaction - N_2O_5 (i n C Cl_4) rarr 2NO_2+1/2 O_2 (g) is first order in N_2O_5 with rate constant 6.2xx10^-4 s^-1 . What is the value of rate of reaction when [N_2O_5] = 1.25 mol L^-1 ?

For the decomposition of N_(2) O_(5) given as, N_(2) O_(5) (g) to N_(2) O_(4) (g) + 1//2O_(2) (g) If the rate law =K [N_(2) O_(5) ] and K=1.68 xx 10^(-2)" s"^(-1) , starting with 2.5 moles, of N_(2) O_(5)(g) in a 5.0"L" container at 298K, how many moles of N_(2) O_(5) would remain after 1.0 minutes?